Source : https://leetcode-cn.com/problems/check-if-grid-satisfies-conditions/

func satisfiesConditions(grid [][]int) bool {
	n := len(grid)
	m := len(grid[0])
	
	for i:=0; i<n; i++ {
		for j:=0; j<m ;j++ {
			// 不能等于下一个
			if i+1<n&&grid[i][j] != grid[i + 1][j]{
				return false
			}
			if j+1<m&&grid[i][j] == grid[i][j + 1]{
				return false
			}
		}
	}
	return true
}